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Sudoku №130501

4 80%
4.7
27
76
25m.17s.
x3
55
2013-10-11 00:00
00:00
Start 20
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golda 37
2017-01-22 22:08
tears

Like + 0     1
bendigodel 44 Solver Rank  2017-04-16 20:47 + 0
Да, только "метод вариантов", а обычной логикой... ну никак.tears
mari58 46
2017-04-01 16:10
rose

Like + 0     0
3g600 21
2018-03-07 22:19
Строго логическое решение существует.
SPOILER
1(54). EK/Q: g9= 3
2(53). EK/Q: d9= 8
3(52). EK/H: b3= 1
4(51). EK/Q: d6= 4
5(50). EK/H: a6= 9
6(49). EK/H: b6= 7
7(48). EK/V: c4= 8
8(47). EK/Q: h5= 8
9(46). EK/P: e9= 4
10(45). EK/P: e7= 6
--(45). Г2/Q: (a8,b8)=(6,8)-->a8<>5, a8<>7, a8<>4, b8<>5, b8<>4,
11(44). EK/H: i8= 5
--(44). Г2/Q: (h2,i2)=(1,7)-->h2<>4, h2<>9, i2<>4, i2<>9,
--(44). Г4/H: (a1,b1,d1,f1)=(2,5,6,8)-->f1<>4, f1<>9,
--(44). Г2/Q: (f3,f2)=(4,9)-->f2<>6,
--(44). Г2/V: (a8,a1)=(6,8)-->a1<>5,
--(44). ЕР/V: (a8/b8,a1/b1)<>(6/8)-->b1<>6,b1<>8,
12(43). EK/Q: a1= 8
13(42). EK/Q: b2= 6
14(41). EK/Q: a3= 4
15(40). EK/Q: b7= 4
16(39). EK/Q: f2= 4
17(38). EK/Q: a8= 6
18(37). EK/Q: b8= 8
19(36). EK/Q: f3= 9
20(35). EK/Q: c2= 9
21(34). EK/Q: c3= 3
22(33). EK/Q: a7= 3
23(32). EK/Q: b4= 3
24(31). EK/Q: b5= 2
25(30). EK/Q: d2= 3
26(29). EK/Q: a4= 5
27(28). EK/Q: c9= 5
28(27). EK/Q: c7= 2
29(26). EK/Q: e5= 5
30(25). EK/Q: b1= 5
31(24). EK/Q: d3= 5
32(23). EK/Q: a9= 7
33(22). EK/Q: e4= 9
34(21). EK/V: d1= 2
35(20). EK/Q: f1= 6
36(19). EK/V: h7= 9
37(18). EK/V: h2= 1
38(17). EK/Q: i2= 7
39(16). EK/H: d7= 7
40(15). EK/Q: f9= 1
41(14). EK/Q: i7= 1
42(13). EK/Q: d4= 1
43(12). EK/Q: f8= 2
44(11). EK/Q: i9= 2
45(10). EK/Q: g4= 2
46(9). EK/Q: d5= 6
47(8). EK/Q: i4= 6
48(7). EK/Q: h4= 4
49(6). EK/Q: g8= 4
50(5). EK/Q: i1= 4
51(4). EK/Q: h8= 7
52(3). EK/Q: f4= 7
53(2). EK/Q: g5= 7
54(1). EK/Q: i5= 9
55(0). EK/Q: g1= 9


Like + 0     0
yura-baidala 32
2021-05-13 09:05
решается легко чистая логика

Like + 1     0
BryanskMyaso 34 Solver Rank
2021-06-30 12:00
Все отлично сошлось без подбора! Ключевой момент: принцип единственности среди пар 6 и 8

Like + 1     0
Aleks257r 42 Solver Rank
2022-11-16 17:59
Без подбора.

Like + 1     0
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